The magnitude of the force that a spring exerts (f) when it is stretched a distance x from its unstressed length is governed by hooke's law, f = kx. (a) what are the dimensions of the force constant, k? (use the following as necessary: m for mass, t for time, and l for length.)

k =  M / T^2

Explanation:

Hooke's law states that the lengthening of a spring is directly proportional to the force module applied to it, provided that the spring is not permanently deformed.

F = k * L

So:

k = F / L

Where :

[F] = N (Newton units)

[L] = m (meter)

[k] = N / m

N = ( M * L ) / T^2

[N] = ( kg * m ) / s^2

Finally:

[k] = ( kg * m ) / ( m * s^2 )

[k] = kg / s^2

k = M / T^2

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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