Beth, a construction worker, attempts to pull a stake out of the ground by pulling on a rope that is attached to the stake. the rope makes an angle of 44.2°with the horizontal. if beth exerts a force of 153.8 n on the rope, what is the magnitude of the upward component of the force acting on the stake? answer in units of n.

Fy=107.2 N

Explanation:

Conceptual analysis

For a right triangle :

sinβ = y/h formula (1)

cosβ = x/h formula (2)

x: side adjacent to the β angle

y:  opposite side of the β angle

h: hypotenuse

Known data

h = T = 153.8 N : rope tension

β= 44.2°with the horizontal (x)

Problem development

We apply the formula (1) to calculate Ty : vertical component of the rope force.

sin44.2° = Ty/153.8 N

Ty = (153.8 N ) *(sen44.2°)= 107.2 N  directed down

for equilibrium system

Fy= Ty=107.2 N

Fy=107.2 N upward component of the force acting on the stake

the diagram which shows forces as either balanced = same speed or unbalanced = accelerarting