Abox with a mass of 10 kg is pulled across the floor at a constant speed by a horizontal rope with a tension of 36n. what is the coefficient of kinetic friction between the box and the floor?

μk = 0.397

Explanation:

Given Data:

m= 10 kg

 Fk=36

To Fnd:

  μk =?

Soluton:

we know that

   Fk= Fn*μk

Fn= mg = 10*9.81 = 98.1 N

    μk= Fk/Fn

      μk= 36/98.1

      μk = 0.397

this isn't the answer but they're the graphs

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.