Acar is traveling at 58.2 km/h on a flat highway. the acceleration of gravity is 9.81 m/s 2 . a) if the coefficient of kinetic friction between the road and the tires on a rainy day is 0.178, what is the minimum distance needed for the car to stop? answer in units of m.\

The answer is 75.4 meters

Explanation:

The car is traveling with constant velocity, when the car stop the fritcion force will reduce the velocity to zero, so:

so using the accelerated motion formulas:

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation