The heat loss from a boiler is to be held at a maximum of 900btu/h ft2 of wall area. what thickness of asbestos (k= 0.10 btu/h ft ℉) is required if the inner and outer surfaces of the insulation are to be 1600 and 500℉, respectively? now if a 3-in.-thick layer of kaolin brick (k= 0.07 btu/h ft ℉) is added to the outside of the asbestos, what heat flux will be result if the outside surface of the kaolin is 250℉? what will be the temperature at the interface between the asbestos and kaolin for this condition?

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

read more on -

50 inches should be the resultant vector

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)

that would be because of both gravity and friction. so     c