Two blocks are attached to opposite ends of a massless rope that goes over a massless, frictionless, stationary pulley. one of the blocks, with a mass of 5.0 kg accelerates downward at 34g.
what is the mass of the other block?

mass of other block is 0.7142 kg

Explanation:

given data

mass = 5.0 kg

accelerates downward =

to find out

mass of other block

solution

we will apply here Newton 2nd law that is

force ∑Fy = mass × acceleration

so

t - mg = ma    .............1

t = 5 ( 9.8 + )

t = 12.25 N

so other block mass is from equation 1

t - mg = ma  

t = m ( g+a)

12.25 = m ( g +   )

12.25 = m ( 9.8

m = 0.7142 kg

mass of other block is 0.7142 kg

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.