An object acted on by three forces moves with constant velocity. one force acting on the object is in the positive x direction and has a magnitude of 6.7 n; a second force has a magnitude of 4.5 n and points in the negative y direction. find the direction and magnitude of the third force acting on the object. ndegrees (counterclockwise from the +x axis)

F= 8.07N : Magnitude of the third force acting on the object

β =33.88° , above the negative axis of the x, magnitude of the third force acting on the object

Explanation:

Conceptual analysis

Newton's first law says that an object is in equilibrium if it remains at rest or if it moves at constant speed, then, the sum of forces must be equal to zero:

Nomenclature

Fx: Component of the third force in x direction.

Fy: Component of the third force in x direction.

Problem development

∑Fx=0

Fx+6,7N=0

Fx= -6.7N

∑Fy=0

Fy-4.5N=0

Fy= +4.5N

Magnitude of the third force (F)

F= 8.07N

Direction of the third force (β)

β =33.88° , above the negative axis of the x

Look at the graph of F in the attached graph

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explanation: