A50.0-kg crate is being pulled along a horizontal smooth surface. the pulling force is 10.0 n and is directed 20.0° above the horizontal. what is the magnitude of the acceleration of the crate?

Explanation:

Assuming the crate does not lift above the ground and remains along the floor, then its acceleration will be in the horizontal direction. Therefore, we can use Newton's second law to find its acceleration:

where

is the net force on the crate along the x-direction

m is the mass of the crate

is the acceleration

Here we have:

m = 50.0 kg

is the component of the pulling force along the horizontal direction

Solving for the acceleration,

the second one and the forth one are in the purple because they are opinions and the rest are in the yellow

explanation: