Atoy rocket engine is securely fastened to a large puck that can glide with negligible friction over a horizontal surface, taken as the xy plane. the 4.20-kg puck has a velocity of 1.60î m/s at one instant. eight seconds later, its velocity is (6.00î + 4.0ĵ) m/s. (a) assuming the rocket engine exerts a constant horizontal force, find the components of the force.

to the right.

to in the upwards direction.

Explanation:

In order to solve this problem, we must first start by drawing a diagram of the situation. (See attached diagram).

So, remember that a force is determined by multiplying the mass of the parcticle by its acceleration:

F=ma

so in order to find the components of the force, we need to start by finding its acceleration.

Acceleration is found by using the following formula:

so we can subtract the two vectors, like this:

which yields:

or:

so now I can find the components of the force:

which yields:

F=(2.31i+2.1j)N

so the components of the force are:

to the right.

to in the upwards direction.

i would say the answer is food.

hope this !

f=ma newton's second law 7x8=56n