Anonconducting sphere has radius r = 2.81 cm and uniformly distributed charge q = +2.35 fc. take the electric potential at the sphere's center to be v0 = 0. what is v at radial distance from the center (a) r = 1.60 cm and (b) r = r? (hint: see an expression for the electric field.)

(a). The electric potential at 1.650 cm is .

(b). The electric potential at 2.81 cm is .

Explanation:

Given that,

Radius of sphere R=2.81 cm

Charge = +2.35 fC

Potential at center of sphere

(a). We need to calculate the potential at a distance r = 1.60 cm

Using formula of potential difference

The electric potential at 1.650 cm is .

(b). We need to calculate the potential at a distance r = R

Using formula of  potential difference

The electric potential at 2.81 cm is .

Hence, This is the required solution.

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s