Ahorizontal circular turntable rotates about its center at the uniform rate of 10.9 revolutions per minutes. find the greatest distance (in meter) from the center at which a small block will remain stationary relative to the turn table. the coefficient of static friction between the turntable and the object is 0.8.

6.03 m

Explanation:

First of all, let's convert the angular velocity from revolutions per minute to radians per second:

The frictional force on the block ranges from zero to a maximum value of

In order for the block to remain stuck on the turntable, the frictional force must be equal to the centripetal force, so we can write:

where

m is the mass of the block

is the angular velocity

r is the distance of the block from the centre

is the coefficient of static friction

g = 9.8 m/s^2

Solving for r, we find:

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