Physics, 09.10.2019 18:30 jadawada223

How do the elements in the noble gas family compare?

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Answer from: dekhua

Noble gases are the most stable chemical elements because they have completely filled valence shells containing the maximum number of electrons it can hold. Noble gases forms Group 18 in the modern periodic table. The order down the periodic table is as follows:

helium (He)

neon (Ne)

argon (Ar)

krypton (Kr)

xenon (Xe)

radon (Rn)

oganesson (Og)

Comparison:

The atomic mass increases as we move down the column because the number of neutrons and protons increase.

The melting and boiling points of the noble gases increases down the group. The reason is that the size of the atom increases downwards. Noble gases have London Dispersion Forces between them. As the dispersion increases, the London Dispersion Forces have more chances of forming a bond. Stronger bonds down the group means higher melting and Boiling points.

Similarly, the density of noble gases increases down the group as stronger forces are there between atoms.

The ionization energy decreases down the group of Noble gases because the electrons in bigger noble gases are located away from the nucleus and held less tightly by the atom.

Compared to other elements, Noble gases have low Melting and Boiling points.

Answer from: Quest

The answer is a 0.64 volts

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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