It has been claimed that an insect called the froghopper (philaenus spumarius) is the best jumper in the animal kingdom. this insect can accelerate at 4 000 m/s2 over a distance of 2.0 mm as it straightens its specially designed " jumping legs." assuming a uniform acceleration, what is the velocity of the insect after it has accelerated through this short distance.

v=4m/s

Explanation:

The formulas for accelerated motion are:

We can derive the formula from them.

We have:

And substitute:

Where in the first step of the last row we just multiplied everything by 2a. Since is the displacement d, we have proved that

We use then our values to calculate the final velocity when starting from rest, traveling a distance 0.002m with acceleration :

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

resonant frequency