Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. you have determined that the football would travel 15.1 m before landing. how would this value change if the football was kicked at an angle of 35.0°?

Increase to 18.5 m

Explanation:

For a projectile launched on flat ground:

d = v² sin(2θ) / g

where d is distance traveled,

v is initial velocity,

g is acceleration due to gravity,

and θ is the launch angle relative to the horizontal.

When θ = 25.0°:

15.1 m = (13.9 m/s)² sin(2×25.0°) / g

g = 9.80 m/s²

Using this value for g, we can find the distance when θ = 35.0°:

d = (13.9 m/s)² sin(2×35.0°) / (9.80 m/s²)

d = 18.5 m

The distance traveled would increase to 18.5 m.

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