Amass weighing 16 lb stretches a spring 3 in. the mass is attached to a viscous damper with a damping constant of 2 lb · s/ft. if the mass is set in motion from its equilibrium position with a downward velocity of 3 in/s, find its position u at any time t. (use g = 32 ft/s2 for the acceleration due to gravity. let u(t), measured positive downward, denote the displacement in feet of the mass from its equilibrium position at time t seconds.)

Where is the table ? you can take a picture of it

The answer is b hope this

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Distance covered = speed x timethe distance traveled going against the stream = distance traveled with the stream.therefore it is the speed and the time that are the variables.as he travels the same distance both ways, speed x time is the same for each way.going upstream his speed is 4 kph; going downstream his speed is 6 kph.therefore we have two simultaneous equations: time upstream x 4 = time downstream x 6time upstream + time downstream = 60 minutestherefore we have the equation: time upstream = 6/10 hour, time downstream therefore = 4/10 hour.distance traveled at 4km/hr in 6/10 hour = 24/10 = 2.4km.check: distance traveled at 6km/hr in 4/10 hour = 24/10 = 2.4km.