An average human weighs about 650 n. if each of two average humans could carry 1.0 c of excess charge, one positive and one negative, how far apart would they have to be for the electric attraction between them to equal their 650@n weight?

Distance, r = 3721.04 meters

Explanation:

It is given that,

Charges on both humans,

Electric force of attraction between them, F = 650 N

We need to find the separation between two humans. It can be solved using the following formula as :

r = 3721.04 meters

So, the distance between the humans is 3721.04 meters. Hence, this is the required solution.

nec chapter 5 contains

c. information on special occupancy areas

nec chapter 6 covers

a. special equipment

which of the following rules contain the words shall or shall not and must be adhered to?

b. mandatory rules

which of the following rules identify actions that are allowed but not required and typically cover options or alternative methods?

c. optional rules

which of the following serves as the introduction to the nec and provides an overview of the book?

a. nec article 90

organizations that test products for safety are

c. nrtls

the nec is published by the

a national fire protection association

the nec is divided into

b. 9 chapters

the nec provides informative annexes for

c. informational materials and examples

two terms from nec article 100 that trainees should become familiar with are

b. labeled and listed

explanation:

answer would be letter choice (a),   a ball resting on a shelf. would be another example of potential energy   >   stored energy > not moving.

a ball spinning on a finger   >   kinetic energy > moving energy

a ball rolling on the ground   >   kinetic energy   > moving energy

a   ball flying through the air   > kinetic energy   >   moving energy

hope that                                         : )