Aball rolls down the hill which has a vertical height of 15 m. ignoring friction what would be the gravitational potential energy of the ball when it is at the top of the hill? what would be the velocity of the ball when it reaches the bottom of the hill?

a) Potential energy: 147 m [J]

The gravitational potential energy of an object is given by

where

m is its mass

is the acceleration of gravity

h is the height of the object above the ground

In this problem,

h = 15 m

We call 'm' the mass of the ball, since we don't know it

So, the potential energy of the ball at the top of the hill is

(J)

b) Velocity of the ball at the bottom of the hill: 17.1 m/s

According to the law of conservation of energy, in absence of friction all the potential energy of the ball is converted into kinetic energy as the ball reaches the bottom of the hill. Therefore we can write:

where

v is the final velocity of the ball

We know from part a) that

U = 147 m

Substituting into the equation above,

And re-arranging for v, we find the velocity:

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.