Physics, 07.10.2019 18:20 dbih2014

A2.0 g metal cube and a 4.0 g metal cube are 6.0 cm apart, measured between their centers, on a horizontal surface. for both, the coefficient of static friction is 0.65. both cubes, initially neutral, are charged at a rate of 7.0 nc/s .

(a) which cube moves first?

(b) how long after charging begins does one cube begin to slide away?

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Answer from: DnakMeme6e7272727272

(a). The 2.0 g metal cube move fast than the 4 g metal cube.

(b). The time taken is 10.19 sec.

Explanation:

Given that,

Mass of metal cube = 2.0 g

Mass of second metal cube = 4.0 g

Coefficient of static friction = 0.65

Charging rate = 7.0 nC/s

Distance = 6.0 cm

(a). We need to calculate the frictional force for 2.0 g metal cube

Using formula of frictional force

$F_{1}=\mu\ mg$

Put the value into the formula

$F_{1}=0.65\times2.0\times10^{-3}\times9.8$

$F_{1}=12.74\times10^{-3}\ N$

The frictional force for 4.0 g metal cube

$F_{2}=0.65\times4.0\times10^{-3}\times9.8$

$F_{2}=25.48\times10^{-3}\ N$

The motion of the cube is less when the friction is more.

The 2.0 g metal cube is having less frictional force.

Therefore, the 2.0 g metal cube move fast than the 4 g metal cube.

(b). We need to calculate the time

Firstly we need to calculate the charge

Using electrostatic force and frictional force

$F=\mu\ mg$

$\dfrac{kq^2}{r^2}=12.74\times10^{-3}$

Put the value into the formula

$9\times10^{9}\times\dfrac{q^2}{(6.0\times10^{-2})^2}=12.74\times10^{-3}$

$q^2=\dfrac{12.74\times10^{-3}\times(6.0\times10^{-2})^2}{9\times10^{9}}$

$q^2=\sqrt{5.096\times10^{-15}}$

$q=7.138\times10^{-8}\ C$

The time taken after charging beings is

$t=\dfrac{q}{C}$

Put the value into the formula

$t=\dfrac{7.138\times10^{-8}}{7.0\times10^{-9}}$

$t=10.19\ sec$

Hence, (a). The 2.0 g metal cube move fast than the 4 g metal cube.

(b). The time taken is 10.19 sec.

Answer from: Quest

Is a vector quantity that refers to "the rate at which an object changes its position." imagine a person moving rapidly - one step forward and one step back - always returning to the original starting position. while this might result in a frenzy of activity, it would result in a zero velocity. because the person always returns to the original position, the motion would never result in a change in position. since velocity is defined as the rate at which the position changes, this motion results in zero velocity. if a person in motion wishes to maximize their velocity, then that person must make every effort to maximize the amount that they are displaced from their original position. every step must go into moving that person further from where he or she started. for certain, the person should never change directions and begin to return to the starting position.

Answer from: Quest

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A2.0 g metal cube and a 4.0 g metal cube are 6.0 cm apart, measured between their centers, on a hori...