Arocket is launched from rest and moves in a straight line at 30.0 degrees above the horizontal with an acceleration of 35.0 m/s2. after 25.0 s of powered flight, the engines shut off and the rocket follows a parabolic path back to earth. find the time of flight from launch to impact. hint: simple projectile motion after engines are shut down.

t = 123.59s

Explanation:

For the launch pad section:

Vf = Vo + a*t  where Vo=0.

Vf = 35*25 = 875m/s

The distance traveled during the launch:

Now the projectile motion, we know that its initial speed is the speed calculated previously and the initial height is the y-component of the previously calculated distance.

 where d= 10937.5m; Vo=875m/s.

Solving for t:

t1 = -11.093s   t2 = 98.59s

So, the total time of flight will be:

there are no components of a physical goal mentioned on the list of choices that you've provided.

one "light year" is the distance that light travels, through vacuum, in one julian year.   that's 365.25 days, of 24 hours each.