During a storm, a tree limb breaks off and comes to rest across a barbed wire fence at a point that is not in the middle between two fence posts. the limb exerts a downward force of 286 n on the wire. the left section of the wire makes an angle of 12.7° relative to the horizontal and sustains a tension of 433 n. find the (a) magnitude and (b) direction (as an angle relative to horizontal) of the tension that the right section of the wire sustains.

Explanation:

Weight, W = 286 N

Tension in the left wire, T1 = 433 N

α = 12.7°

let the tension in the right wire is T2 and angle with the horizontal is β.

Make the components and maintain the equilibrium

(a)

Equilibrium of forces along x axis

   .... (1)

Equilibrium of forces along y axis

    .... (2)

Squarring equation (1) and (2) and then add

T2 = 463.5 N

(b) Divide equation (2) by (1)

β = 24.2°

(a) T2 be the tension in right wire

Use

diagram is missing, but i will try to explain your doubt.

answer:

amplitude is the maximum displacement or distance moved on a point of a vibrating body or wave measured from its equilibrium position.it is equal to half the length of vibration path.

i think the answer is tomato juice? not entirely sure though