In this problem you’ll consider objects at the extreme ends of astronomical density scale. you can assume that all objects given below are spherical and of uniform density. recall that volume of a sphere of radius r is v = 4r3π/3. the only formula you’ll need is m = rho∗v where rho is the density of the object, m is its mass and v its volume. (a) assume that the density of a neutron star is 5 ∗ 1017kg/m3. what is the mass of one teaspoon of neutron star matter? you can assume that the standard teaspoon volume is 5ml = 5 ∗ 10−6m3. (b) assuming the same density, what is the radius of a neutron star with mass equal to two solar masses? (c) molecular clouds are the birthplace of stars. a typical molecular cloud has density of rho = 1.67 ∗ 10−19kg/m3. what is the diameter of a cloud with mass equal to one solar mass? give your answer both in meters and in light years. (the answer in (c) will give you the minimal size of the part of the cloud needed for the creation of the solar system. a typical total size of the protostellar cloud is much, much larger.)

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

do you have a formula possibly

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

3. dark matter

empty space could also be a simple vacuum