We measure a voltage difference of 5.0 v between two points on the conducting paper between two parallel conducting electrodes. if these two points are separated by 3.0 mm in a direction 24° with respect to the perpendicular to the electrodes, what is the magnitude of electric field at this location on the conducting paper and in which direction does the field point?

E=1824.81 V/m

Explanation:

Given that

Voltage difference = 5 V

Distance ,D= 3 mm

 θ = 24°

As we know that electric filed given as

Given that D is 24° with respect to the perpendicular to the electrodes.So we have to take cos component of D.

d= D cosθ

d= 3 cos24°

d = 2.74 mm

So

E=1824.81 V/m

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.

second mirror gathers light from a faraway object and reflects it to another mirror. - a.