A260-m-wide river flows due east at a uniform speed of 4.1m's a boat with a speed of 7 5ms relative to the water leaves the south bank pointed in a direction 37 west of north. what is the (al magnitiale and tb) direction ot the bat's velocity relative to the ground? give the direction as the anele of the velocity from due north positive if to the east and nepative if to the west. ld) how long does it take for the boat to cross the river?

the answer is 3.1 his answer is wrong mines is right

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west