Your friend of mass 80 kg can just barely float in freshwater. calculate her approximate volume.
express your answer to two significant figures and include the appropriate units.

0.080 m³

Explanation:

According to Archimedes' principle:

The weight of the fluid dispersed by the object is equal to the weight of the object which is floating on the fluid.

Thus, the mass of the friend = 80 kg

The mass of water displaced = 80 kg

Also, The density of fresh water =1000 kg/m³

Volume = mass/density.

So volume of the water displaced = 80 kg /1000 kg/m³ = 0.08 m³.

Thus, the volume of the friend is also equal to this volume = 0.080 m³  ( answer to two significant figures)

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation:

the answer is neither ball has a charge.

because if they were both positively charged, they will repel each other.

if they were positively and negatively charged, they will seek.