Agirl, standing on the roof of a house which is 5.00 m high, throws a stone vertic upward. it strikes the ground 7.00 s after being thrown. calculate: the initial velocity of the stone the maximum height the stone reaches above a. b. i. the roof ii. the ground and c.

Explanation:

Given

Height of roof=5 m

Time taken by stone to reach ground 7 s

Let u be the initial velocity

therefore maximum height is h

time taken to reach max height

v=u+at

0=u-gt

Now time taken to reach ground is

total time is

Squaring both side

u=33.58 m/s

therefore

h=57.55 m

maximum height from ground is 57.55+5=62.55 m

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y