An fcc metal has a lattice spacing of a-3.060 angstroms. calculate the volume (in angstroms) of the interstices (empty space) in the unit cell. volume of the interstices-volume of the unit cell (1-atomic packing factor) where the atomic packing factor for fcc metals is 0.74 änd the volume of a unit cell with the side a will be a 8.9966

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Iisisisisososos9soslslsskosisosisi

Hi. i believe this is called a scientific  theory.cheers!