Anonconducting rod of length l = 8.15 cm has charge –q = -4.23 fc uniformly distributed along its length.(a) what is the linear charge density of the rod? what are the(b) magnitude and(c) direction(relative to the positive direction of the s-axis) of the electric field produced at point p, at a distance a = 12.0 cm from the rod? what is the electric field produced at point p, at distance a = 12.0 cm from the rod? what is the electric field magnitude produced at distance a = 50 m by(d) the rod and(e) a particle of charge –q = -4.23 fc that replaces the rod?

Hey hope you get the answer but i suck at math sorry : (

You would need to take a picture so i can see

stands for electromotive force and it is measured in volts. despite its name, it is not actually the force in the sense of being a "pushing" or "pulling" (not measured in newtons).an equation that relates emf,  ℰ,  to a battery's terminal voltage, v, current, i, and internal resistance, r, is    ℰ = v + irin this case, the emf can be interpreted as a voltage—a difference in electric potential.i would not say that it would be considered an energy. if emf can be defined as the energy/work per a unit charge from a battery or other electric source, then it is not strictly energy.