Acannonball is launched with initial velocity of magnitude v0 over a horizontal surface. at what minimum angle
θmin above the horizontal should the cannonball be launched so that it rises to a height h which is larger than the
horizontal distance r that it will travel when it returns to the ground?
(a) θmin = 76◦
(b) θmin = 72◦
(c) θmin = 60◦
(d) θmin = 45◦
(e) there is no such angle, as r > h for all range problems.

A)   θmin= 76°.

Explanation:

Given that

Speed of cannonball = Vo

Lets take θ is the angle measure from horizontal

We know that

Range R

Height h

Given that h should be larger than R

         h > R

        θ  >75.96°

So minimum angle should be 75.96° or 76°.

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.