In a double slit experiment, if the separation between the two slits is 0.050 mm and the distance from the slits to a screen is 2.5 m, find the spacing between the first-order and second-order bright fringes when coherent light of wavelength 600 nm illuminates the slits.

30 cm

Explanation:

Hi! Lets find the angles for the first and second order maxima

The first order maximum will occur for Ф=0

The second order maximum will satisfy the following relationship:

sinФ = λ/d

Where   λ = 600 x 10^-9 m  and d = 5 x 10^-5 m

Therefore:

sinФ = 0.012

And the vertical distance bewteen the first and second will be given by:

l = (2.5 m) tanФ

But since 2.5 m>>0.05 mm  ;  sinФ≈tanФ

Therefore:

l = (2.5 m) sinФ

l = 0.03 m = 30 cm

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

d. platinum would have the greatest temperature increase because it has the lowest specific heat.