When mapping the equipotentials on the plates with different electrode configurations you may find that some have significant areas with uniform distribution of the equipotential lines. if the distance between such lines is 0.5 cm, what is the electric field there (in units si)? assume the applied potential difference between the electrodes is as recommended in the manual.

v = 10 V and E = 2 10³ N/C

Explanation:

The electrical potentials and the electric field at one point are related by the expression

            ΔV = - ∫ E. dS

Where the bold indicates vector quantities, E is the electric field and S is the line of displacement of the load, in general displacement is perpendicular to the equipotential lines, which reduces the product scales to the ordinary product.

 If the potential difference is the most usual that is V = 10 V, the electric field is

   s = 0.5 cm = 0.5 10⁻² m

                E = ΔV / S

                E = 10/0.5 10⁻²

                 E = 2 10³ N / C

layer a is the exosphere and layer b is the thermosphere.   is the answer i think but i hope this .

float.

archimedes' principle

denser than water sinks in water.

denser than mercury would sink in it