In a particle accelerator, a magnetic force keeps a lithium nucleus (mass 6.02 u) traveling in a circular path with a radius of 0.450 m. the lithium nucleus moves at a speed of 11.00% of the speed of light. what is the magnitude of the magnetic force on the lithium nucleus (in n)?

F = 2.42 × 10⁻¹¹N

Explanation:

given,

mass of lithium nucleus = 6.02 u

radius of the circular path = 0.450 m

speed of the lithium nucleus = 11% of speed of light

                                                = 0.11 × 3 × 10⁸

                                                = 33 × 10⁶ m/s

magnetic force on the lithium nucleus =

                =

                =

              F = 2.42 × 10⁻¹¹N

so, magnetic force of the lithium nucleus is 2.42 × 10⁻¹¹N

resonant frequency

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west