Consider a 2100-kg car cruising at a constant speed of 70 km/h. now, the car starts to pass another car by accelerating to 110 km/h in 13 s. determine the additional power needed to achieve this acceleration. what would your answer be if the total mass of the car were only 700 kg

For 700 kg:

Explanation:

Power is given by the following formula:

Where W is the amount of work done during the time interval Δt.

Recall that work is equal to the change in kinetic energy:

So, we have:

For 700 kg:

prolly a beacuse the momentuem the car has increases while going down hill

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s