Alarge box of mass m is pulled across a horizontal, frictionless surface by a horizontal rope with tension t. a small box of mass m sits on top of the large box. the coefficients of static and kinetic friction between the two boxes are μs and μk, respectively.
1- find an expression for the maximum tension t max for which the small box rides on top of the large box without slipping. express your answer in terms of the variablesm ,m , ms, and appropriate constants.2-a horizontal rope pulls a 10 kg wood sled across frictionless snow. a 6.0 kg wood box rides on the sled. what is the largest tension force for which the box doesn't slip? assume that mk= 0.50.

T = g μ_s ( M+m )

78.4 N

Explanation:

When both of them move with the same acceleration , small box will not slip over the bigger one. When we apply force on the lower box, it starts moving with respect to lower box. So a frictional force arises on the lower box which helps it too to go ahead . The maximum value that this force can attain is mg μ_s . As a reaction of this force, another force acts on the lower box in opposite direction .

Net force on the lower box

= T - mg μ_s = M a    ( a is the acceleration created by net force in M )

Considering force on the upper box

mg μ_s = ma

a = g μ_s

Put this value of a in the equation above

T - m gμ_s = M g μ_s

T = mg μ_s + M g μ_s

=  g μ_s ( M+m )

2 )

Largest tension required

T = 9.8 x  .50 x ( 10+6 )

= 78.4 N

the second one and the forth one are in the purple because they are opinions and the rest are in the yellow

explanation:

depends on what you mean by "group." for order, it would be coleoptera (beetles). for class, it would be insecta (insects). for phylum, it would be the arthropoda (animals with jointed exoskeletons).

explanation: