An aluminum clock pendulum having a period of 1. s keeps perfect time at 20.0°c. when placed in a room at a temperature of -10.2°c, will the clock gain time (run fast) or lose time (run slow)? use 24 x 10^-6 for the expansion coefficient of aluminum.

The clock will run slower

Explanation:

Hi!

The period T of the clock pendulum is related to the length of the wire l

However, when the temperature decreases, the length of the wire will decrease, and therefore the period will decrease.

How much you may ask

We can figure this out dividing the period T at room temperature and T' at -10.2 degrees:

and using the formula for linear thermal expansion:

Therefore:

Where

     α=25x10^-6    1/°C

    ΔT = -10.2 -20 = -30.2°C

Therefore

Or

T' = 0.999622 T

It will run at a 99.96% of its original speed

terd muffin is the correct answer

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation