Adipole with a positive charge of 2.0 uc and a negative charge of -2 uc is centered at the origin and oriented along the x axis with the positive charge located to the right of the origin. the charge separation is 0.0010 m. find the electric field due to this dipole at the point x = 4.0 m, y = 0.0 m.

(a) 0.56 i n/c
(b) -.56 i n/c
(c) 0.28 i n/c
(d) -0.28 i n/c

The reulting electric field at x = 4.0 and y = 0.0 from the dipole is 0.5612 N/C

Solution:

As per the question:

Charges of the dipole, q =

Separation distance between the charges, d = 0.0010 m

Separation distance between the center and the charge, d' =

x = 4.0 m

y = 0.0 m

Now,

The electric field due to the positive charge on the right of the origin:

E =

where

k = Coulomb's constant =

Now,

E =

Similarly, electric field due to the negative charge:

E' =

E' =

Thus

answer: the correct answer is   air pressure at the top of mount everest is higher than at the bottom of the grand canyon.

hope this : )

explanation:

hi i’m sorry to call us today so we will get back with y’all and we will have to do it haha omg was the day