Acar traveling at a constant speed of 30 m/s passes a highway patrol police car which is at rest. the police officer accelerates at a constant rate of 3.0 m/s2 and maintains this rate of acceleration until he pulls next to the speeding car. assume that the police car starts moving at the moment the speeder passes his car. determine the – a) time required for the police officer to catch the speeder and – b) distance traveled during the chase.

a) 20 seconds

b) 600 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

a) Speeder acceleration is 0 as the speed is constant

Police car

The distance they travel will be equal

Time required by the police car to catch the speeder is 20 seconds

b) The distance traveled by the police car will be 1.5×20² = 600 m

frequency or wavelenth of em radiation in a vacuum

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.