Abaseball is popped straight up into the air and has a hang-time of 6.25 s.
determine the height to which the ball rises before it reaches its peak. (hint: the
time to rise to the peak is one-half the total hang-time.)

We have that for the Question "A baseball is popped straight up into the air and has a hang-time of 6.25 S.

Determine the height to which the ball rises before it reaches its peak. (Hint: the  time to rise to the peak is one-half the total hang-time.)" it can be said that Hence, the height to which the ball rises before it reaches its peak is

S=47.85m

From the question we are told

A baseball is popped straight up into the air and has a hang-time of 6.25 S.

Determine the height to which the ball rises before it reaches its peak. (Hint: the  time to rise to the peak is one-half the total hang-time.)

Generally the Newtons equation for the distance   is mathematically given as

Therefore

S=47.85m

Hence, the height to which the ball rises before it reaches its peak is

S=47.85m

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47.9 m

Explanation:

Given:

y₀ = 0 m

t = 6.25/2 = 3.125 s

v = 0 m/s

a = -9.8 m/s²

Find: y

y = y₀ + vt − ½ at²

y = 0 + (0)(3.125) − ½ (-9.8)(3.125)²

y = 47.9 m

when cloud cover increases then the suns ray's which provides the earth with light and warmth gets covered due to the due to the suns ray's being blocked, the temperature in that region

therefore to conclude i would like to say that,

=more the cloud cover, the lesser the

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