Liquid methyl ethyl ketone (mek) flows through a pipe with an inner diameter of 2.067 inches at an average velocity of 0.48 ft/s. at the fluid temperature of 20°c the density of liquid mek is 0.805 g/cm3 and the viscosity is 0.43 centipoise [1 cp 1: 00 103 kg/ m s]. without using a calculator, determine whether the flow is laminar or turbulent. show your calculations.

Turbulent

Explanation:

The Reynolds number is:

Re = ρvL/μ

where ρ is the fluid density,

v is the velocity,

L is the characteristic length (for pipe, it's the diameter),

and μ is the dynamic viscosity.

Given:

ρ = 0.805 g/cm³

v = 0.48 ft/s = 14.63 cm/s

L = 2.067 in = 5.250 cm

μ = 0.43 cp = 0.0043 g/cm/s

Re = (0.805 g/cm³) (14.63 cm/s) (5.250 cm) / (0.0043 g/cm/s)

Re ≈ 14400

Flow is considered turbulent if the Reynolds number is greater than 4000.  So this is turbulent.

i'm just gonna leave this comment here, so i can get a challange done-

explanation:

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂