The net potential energy en between two adjacent ions is sometimes represented by the expression e, m3 + d exp (2.18) in which r is the interionic separation and c, d, and rho are constants whose values depend on the specific material (a) derive an expression for the bonding energy eo in terms of the equilibrium interionic separation ro and the constants d and p using the following procedure: (i) differentiate en with respect to r, and set the resulting expression equal to zero. (ii) solve for c in terms of d, p, and ro i) determine the expression for e by substitution for c in equation 2.18 (b) derive another expression for eo in terms of ro, c, and p using a procedure analogous to the one outlined in part

Answer sample (c); // would be best because the percentage of the energy in an incident wave that remains in a reflected wave from this material is the smallest;

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge

Answer mechanical energy;