You are on a train that is traveling at 3.0 m/s along a level straight track. very near and parallel to the track is a wall that slopes upward at a 12° angle with the horizontal. as you face the window ( 0.830 m high, 2.34 m wide) in your compartment, the train is moving to the left, as the drawing indicates. the top edge of the wall first appears at window corner a and eventually disappears at window corner b. how much time passes between appearance and disappearance of the upper edge of the wall?

Total time passed = 2.085 seconds

In the question,

Speed of the train to the left, v = 3 m/s

The slope of the wall (with horizontal) = 12°

Height of the window = 0.83 m

Width of the window = 2.34 m

Now,

The time is needed to be find out for the top edge of the wall to reach the point B (top right) from A (bottom left).

So,

First calculating the time taken by the Wall's top point to reach B in he horizontal is,

Now,

Time taken to reach the top point of the wall up to the height of the window to reach point B is,

Time = Distance traveled by the train in the horizontal until wall reaches B/ Speed of the train

So,

So,

Time taken by the train to cover this distance is,

Therefore, the total time for the point to reach B from A is,

Time = 0.78 + 1.305 = 2.085 seconds

Therefore, Total Time = 2.085 s

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unbalanced force

explanation: