Suppose our experimenter repeats his experiment on a planet more massive than earth, where the acceleration due to gravity is g=30 m/s2. when he releases the ball from chin height without giving it a push, how will the ball's behavior differ from its behavior on earth? ignore friction and air resistance.
a. it will take more time to return to the point from which it was released.
b. it will smash his face. it will take less time to return to the point from which it was released.
c. it will stop well short of his face.
d. its mass will be greater.

B It will takes less time

Explanation:

Let's analyze this problem as a free fall with a greater acceleration of gravity, let's calculate the time it takes to reach the ground

     Y = Vo + + ½ at2

In this case Vo is zero and a = -30 m / s2

     Y = - ½ to t²

     t= √2y / a

     t =√ 2y / 30

Earth's time is t2 = √2y / 9.8

      t < t2

We can see that the time it takes for the ball to reach the floor is reduced, the rise time is the same as the drop.  The total time would be 2t on the massive planet and on Earth 2t2

So by comparing the results with those obtained on Earth the ball takes less time to return to the point of departure

terd muffin is the correct answer

cant without the picture! ?