P2.008 a steel cable is used to support an elevator cage at the bottom of a 1800-ft-deep mineshaft. a uniform normal strain of 200.0 in./in. is produced in the cable by the weight of the cage. at each point, the weight of the cable produces an additional normal strain that is proportional to the length of the cable below the point. assume d = 1800 ft and d = 700 ft. if the total normal strain in the cable at the cable drum (upper end of the cable) is 790 in./in., determine (a) the strain in the cable at a depth of 700 ft. (b) the total elongation of the cable.

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~

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r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.