At exactly 3: 14pm, the velocity of a dog running in a park points toward a group of flowers. which of the following best describe the forces acting on the dog at 3: 14pm?
there may be many forces acting on the dog, but the forces pointing toward the flowers are larger than the forces pointing away from the flowers.
there may be many forces acting on the dog, but the forces pointing toward the flowers are smaller than the forces pointing away from the flowers.
there may be many forces acting on the dog, but the forces pointing toward the flowers are equal to the forces pointing away from the flowers.
options a and b are both possible.
options a and c are both possible.
options a, b, and c are all possible.

Options A, B, and C are all possible.

Explanation:

We know that the instantaneous velocity of the dog at 3:14PM is possitive to toward the flowers. But what about the acceleration to toward the flowers?

If the dog is decreasing speed at 3:14PM, it means that acceleration is negative toward the flowers, hence (since F=ma) the net force points away from the flowers.

If the dog is increasing speed at 3:14PM, it means that acceleration is positive toward the flowers, hence (since F=ma) the net force points toward the flowers.

If the dog is not increasing nor decreasing speed at 3:14PM, it means that acceleration is 0, hence (since F=ma) the net force is null and it does not point neighter to toward the flowers  nor away from the flowers. This happens when the forces acting on the dog are equal to both sides.

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.

i believe the answer is a hope it and is correct