Two parallel plates 1.0 cm apart are equally and oppositely charged. an electron is released from rest at the surface of the negative plate and simultaneously a proton is released from rest at the surface of the positive plate. how far from the negative plate is the point at which the electron and proton pass each other?

 the proton and electron will be met almost at the positive plate. Aproximatelly 1 cm from the negative plate.

Explanation: Both particles when are released in the electric field have both field a force given by: F= q*E, Then the electron moves to the left while the proton to the right. They will met very close to positive plate. This fact is due the different acceleration that each particle feel. This means the proton feel a weak acceleration due to its bigger mas, The proton mass in 1836 times higher than the electron.

The equationa are teh following

For the proton Fp=mp*ap

Fp=e*E

For the electron Fe=me*ae

The kinematic equation are:

From the lest 8 negative plate

x=ae*t^2/2

D-x=ap*t^2/2

combining these we can obtain x.

correct it is c.) b b