Two identical asteroids travel side by side while touching one another. if the asteroids are composed of homogeneous pure iron and are spherical, what diameter in feet must they have for their mutual gravitational attraction to be 1 lb?

diameter = 21.81 ft

Explanation:

The gravitational force equation is:

Where:

We also know that the asteroids are identical so their masses are identical:

Since R is the distance between centers of the two asteroids and their diameters are identical (see attachment), we can conclude that:

We don´t know the mass of the asteroids but we know they are composed of pure iron, so we can relate their masses to their density:

This is going to be helpful because the volume of a sphere is:

And know we can write our original force of gravity equation in terms of the radius of the asteroids:

Now let´s plug in the values we know:

Solve for r and multiply by 2 because 2r = diameter

Result is d = 21.81 Feet

graphing motion: mastery test

209be

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the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2

laticia draws the diagram below to show earth’s magnetic field.

answer

the arrows to the right of earth should point up.