Determine the horizontal position x of the cart at t=9.0 s if the cart is located at x =2 m at t = 0

Horizontal position X is 1.1 m

Given:

Initial time t = 0 sec

Final time T = 9 sec

Initial velocity u = 0.8 m/s

Final velocity v = -1 m/s

Initial position X₀ = 2 m

Find:

Horizontal position X

Computation:

We know that;

a = (v - u) / Δt

So,

a = (-1 - 0.8) / (9 - 0)

a = -1.8 / 9

a = -0.2 m/s²

The equation for position X

X = ut + (1/2)(a)(t²) + X₀

X = (0.8)(9) + (1/2)(-0.2)(9²) + 2

X = 7.2 + (-0.1)(81) + 2

X = 9.2 - 8.1

X = 1.1 m

Horizontal position X = 1.1 m

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1.1m

Explanation:

Given values: time t = 9s, initial position x₀ = 2m, Values from the graph:

initial velocity v₀= 0.8m/s, constant acceleration a = -0.2m/s²(slope of the graph between time t = 0 and t = 9s)

The equation for position x and a constant acceleration is given by:

Using the given values to solve for x:

answer: the direction of the wind is expressed as the direction from which the wind is blowing. for example, easterly winds blow from east to west, while westerly winds blow from west to east.

explanation:

the answer is b, have negligible mass