Much of the energy released in catabolic reactions is captured in atp for use in other reactions. when the phosphate is transferred directly from an organic molecule to adp in order to produce atp without an energized membrane, what has occurred?
a. substrate-level phosphorylation
b. oxidative phosphorylation
c. noncyclic photophosphorylation
d. cyclic photophosphorylation

A substrate-level phosphorylation

Explanation:

Large amount of energy released in catabolic reactions is captured in ATP for use in other reactions. The conversion of ADP into ATP With transfer of phosphate from ADP without an energized membrane. This process is called  substrate-level phosphorylation.

substrate-level phosphorylation is metabolic reaction in which ADP is converted to ATP by direct transfer of Phosphoryl Group (PO3) to ADP.

the velocity you are looking for is made up of two parts: horizontally velocity, vh, and its vertical velocity, vv. the actual velocity of the ball will be these two parts added together, and because velocity is a vector then they will need to be added vectorially.  

neglecting air resistance etc etc.,  

the horizontal velocity component will be constant (because there is no accelerating force in the horizontal direction.  

vh = 8 ms-1  

the vertical velocity component has an accelerating force: 'g'.  

using v = u +at where a = g = 9.81 ms-2.  

the vertical component of velocity, vv = 0 + gt = vv =9.81 x 2  

vv = 19.62 ms-1 . the zero appears because the virtical component of velocity at time t=0 is zero. remember, the ball was thrown horizontally.  

how fast it will be moving (it actual path (being a parabola )) will be the vector sum of these two.  

adding vectorally gives: -  

v = sqr root (8^2 + 19.62^2) = sqr root(64+384.9) = 21.18 or 21.2 ms-1

33: i think it’s b