Two point charges are fixed on the y axis: a negative point charge q1 = -25 μc at y1 = +0.18 m and a positive point charge q2 at y2 = +0.34 m. a third point charge q = +8.4 μc is fixed at the origin. the net electrostatic force exerted on the charge q by the other two charges has a magnitude of 25 n and points in the +y direction. determine the magnitude of q2.

Explanation:

The magnitude of the net force exerted on q is known, we have the values and positions for and q. So, making use of coulomb's law, we can calculate the magnitude of the force exerted by on q. Then we can know the magnitude of the force exerted by about q, finally this will allow us to know the magnitude of

exerts a force on q in +y direction, and exerts a force on q in -y direction.

The net force on q is:

Rewriting for :