If you swim with the current in a river, your speed is increased by the speed of the water; if you swim against the current, your speed is decreased by the water's speed. the current in a river flows at 0.52 m/s. in still water you can swim at 1.73 m/s. if you swim downstream a certain distance, then back again upstream, how much longer, in percent, does it take compared to the same trip in still water?

11.23%

Explanation:

Lets take

Speed of man in still water =u= 1.73 m/s

Speed of flow of water = v=0.52 m/s

When swims in downward direction then speed of man = u + v

When swims in upward direction then speed of man = u - v

Lets time taken by man when he swims in downward direction is and when he swims in downward direction is

Lets distance is d and it will be remain constant in both the case

Time taken in still water

2 d= t x 1.73

t=1.15 x d sec

total time in current = 0.82 +0.44 d=1.26 d sec

So the percentage time

 Percentage time =11.32%

So it will take 11.32% more time as compare to still current.

amplitude

hope this

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m