A100kg cannon at rest contains a 10kgcannonball. when fired,
the cannonball leaves the cannon with avelocity of 90m/s. what is
the magnitude of the recoil speed of thecannon.

9 m/s

Explanation:

mass of cannon, M = 100 kg

mass of cannon ball, m = 10 kg

velocity of cannon ball, v = 90 m/s

Let the recoil velocity of cannon is V.

Us ethe conservation of linear momentum, as no external force is acting on the system, so the linear momentum of the system is conserved.

Momentum before the firing = momentum after the firing

M x 0 + m x 0 = M x V + m x v

0 = 100 x V + 10 x 90

V = - 9 m/s

Thus, the recoil velocity of cannon is 9 m/s.

he made 11 calls in one day

do you have a formula possibly